#include <stdio.h>
int  main()
{
	int t,i,j,n,m,h,sum,a[4000];
	scanf("%d",&t);
	while (t--)
	{
		scanf("%d",&n);
		for (i=1;i<=n;i++)
			a[i]=0; sum=0;
		scanf("%d",&m);
		for (i=1;i<=m;i++)
		{scanf("%d",&h);
			for (j=1;j*h<=n;j++)
				a[j*h]=1;
		}
		for (i=0;7*i<=n;i++)
		{a[7*i]=0;a[7*i+6]=0;}
		for (i=1;i<=n;i++)
			sum+=a[i];
		printf("%d\n",sum);
	}
	return 0;
}

 

相关文章:

  • 2021-10-06
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2021-07-05
猜你喜欢
  • 2021-12-22
  • 2022-12-23
  • 2022-12-23
  • 2021-11-08
  • 2022-12-23
  • 2021-11-25
相关资源
相似解决方案