SELECT DISTINCT <select_list> FROM <left_table> <join_type> JOIN <right_table> ON <join_condition> WHERE <where_condition> GROUP BY <group_by_list> HAVING <having_condition> ORDER BY <order_by_condition> LIMIT <limit_number>
二 SELECT语句关键字的执行顺序
(7) SELECT (8) DISTINCT <select_list> (1) FROM <left_table> (3) <join_type> JOIN <right_table> (2) ON <join_condition> (4) WHERE <where_condition> (5) GROUP BY <group_by_list> (6) HAVING <having_condition> (9) ORDER BY <order_by_condition> (10) LIMIT <limit_number>
三 准备表和数据
1. 新建一个测试数据库TestDB;
create database TestDB;
2.创建测试表table1和table2;
CREATE TABLE table1 ( customer_id VARCHAR(10) NOT NULL, city VARCHAR(10) NOT NULL, PRIMARY KEY(customer_id) )ENGINE=INNODB DEFAULT CHARSET=UTF8; CREATE TABLE table2 ( order_id INT NOT NULL auto_increment, customer_id VARCHAR(10), PRIMARY KEY(order_id) )ENGINE=INNODB DEFAULT CHARSET=UTF8;
3.插入测试数据;
INSERT INTO table1(customer_id,city) VALUES('163','hangzhou'); INSERT INTO table1(customer_id,city) VALUES('9you','shanghai'); INSERT INTO table1(customer_id,city) VALUES('tx','hangzhou'); INSERT INTO table1(customer_id,city) VALUES('baidu','hangzhou'); INSERT INTO table2(customer_id) VALUES('163'); INSERT INTO table2(customer_id) VALUES('163'); INSERT INTO table2(customer_id) VALUES('9you'); INSERT INTO table2(customer_id) VALUES('9you'); INSERT INTO table2(customer_id) VALUES('9you'); INSERT INTO table2(customer_id) VALUES('tx'); INSERT INTO table2(customer_id) VALUES(NULL);
准备工作做完以后,table1和table2看起来应该像下面这样:
mysql> select * from table1; +-------------+----------+ | customer_id | city | +-------------+----------+ | 163 | hangzhou | | 9you | shanghai | | baidu | hangzhou | | tx | hangzhou | +-------------+----------+ 4 rows in set (0.00 sec) mysql> select * from table2; +----------+-------------+ | order_id | customer_id | +----------+-------------+ | 1 | 163 | | 2 | 163 | | 3 | 9you | | 4 | 9you | | 5 | 9you | | 6 | tx | | 7 | NULL | +----------+-------------+ 7 rows in set (0.00 sec)
四 准备SQL逻辑查询测试语句
#查询来自杭州,并且订单数少于2的客户。 SELECT a.customer_id, COUNT(b.order_id) as total_orders FROM table1 AS a LEFT JOIN table2 AS b ON a.customer_id = b.customer_id WHERE a.city = 'hangzhou' GROUP BY a.customer_id HAVING count(b.order_id) < 2 ORDER BY total_orders DESC;
五 执行顺序分析
在这些SQL语句的执行过程中,都会产生一个虚拟表,用来保存SQL语句的执行结果(这是重点),我现在就来跟踪这个虚拟表的变化,得到最终的查询结果的过程,来分析整个SQL逻辑查询的执行顺序和过程。
执行FROM语句
第一步,执行FROM语句。我们首先需要知道最开始从哪个表开始的,这就是FROM告诉我们的。现在有了<left_table>和<right_table>两个表,我们到底从哪个表开始,还是从两个表进行某种联系以后再开始呢?它们之间如何产生联系呢?——笛卡尔积
关于什么是笛卡尔积,请自行Google补脑。经过FROM语句对两个表执行笛卡尔积,会得到一个虚拟表,暂且叫VT1(vitual table 1),内容如下:
+-------------+----------+----------+-------------+ | customer_id | city | order_id | customer_id | +-------------+----------+----------+-------------+ | 163 | hangzhou | 1 | 163 | | 9you | shanghai | 1 | 163 | | baidu | hangzhou | 1 | 163 | | tx | hangzhou | 1 | 163 | | 163 | hangzhou | 2 | 163 | | 9you | shanghai | 2 | 163 | | baidu | hangzhou | 2 | 163 | | tx | hangzhou | 2 | 163 | | 163 | hangzhou | 3 | 9you | | 9you | shanghai | 3 | 9you | | baidu | hangzhou | 3 | 9you | | tx | hangzhou | 3 | 9you | | 163 | hangzhou | 4 | 9you | | 9you | shanghai | 4 | 9you | | baidu | hangzhou | 4 | 9you | | tx | hangzhou | 4 | 9you | | 163 | hangzhou | 5 | 9you | | 9you | shanghai | 5 | 9you | | baidu | hangzhou | 5 | 9you | | tx | hangzhou | 5 | 9you | | 163 | hangzhou | 6 | tx | | 9you | shanghai | 6 | tx | | baidu | hangzhou | 6 | tx | | tx | hangzhou | 6 | tx | | 163 | hangzhou | 7 | NULL | | 9you | shanghai | 7 | NULL | | baidu | hangzhou | 7 | NULL | | tx | hangzhou | 7 | NULL | +-------------+----------+----------+-------------+