leetcode Valid Sudoku

Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

A partially filled sudoku which is valid.

 

不理解数独的概念的人好亏。

1.每行每列的数字是1~9，且不得重复

2.空的填'.'

3.每个九宫格也是数字1~9,且不得重复

 

class Solution {
public:
    bool isValidSudoku(vector<vector<char>>& board) {
        char temp;
        map<char,bool> row;
        map<char,bool> column;
        map<char,bool> grid;
        for(int i=0;i<9;i++){
            //先检查每行
            for(int j=0;j<9;)
            {   
                temp=board[i][j];
                if('1'<=temp<='9'&&!row[temp]) {j++; row[temp]=true;}
                else if(temp=='.') j++;
                else return false;
            }
            row.clear();

        }
        //再检查每列
        for(int m=0;m<9;m++){
            for(int k=0;k<9;)
            {   
                temp=board[k][m];
                if('1'<=temp<='9'&&!column[temp]) {k++; column[temp]=true;}
                else if(temp=='.') k++;
                else return false;
            }
            column.clear();
        }
        //在检查每个九宫格
        int hang=0,lie=0;
        for(int l=0;l<9;l++){
            for(int q=0;q<9;q++){
                hang=(l/3)*3+q/3;
                lie=q%3+(l%3)*3;
                temp=board[hang][lie];
                if('1'<=temp<='9'&&!grid[temp]) {grid[temp]=true;continue;}
                else if(temp=='.') continue;
                else return false;
            }
            grid.clear();
            
        }
        return true;
        
    }
};