百钱买百鸡

#include <stdio.h>
main()
{
    int g, m, x;
    printf("所有可能的解如下：\n");
    for( g=0; g <= 100; g++ )
        for( m=0; m <= 100; m++ )
            for( x=0; x <= 100; x++ )
            {
                if( 5*g+3*m+x/3==100 && x%3==0 && g+m+x==100 )
                {
                    printf("公鸡 %2d 只，母鸡 %2d 只，小鸡 %2d 只\n", g, m, x);
                }
            }
}