题目 代码 #include <iostream> using namespace std; int main(){ int n; cin >> n; int i = 0; while (n != 1){ if (n % 2 == 0){ n = n / 2; i++; } else{ n = (3 * n + 1) / 2; i++; } } cout << i<< endl; return 0; } 分析 很简单 相关文章: 2021-04-03 2021-09-18 2021-12-07 2021-05-09 2022-12-23 2022-12-23 2022-12-23 2022-12-23