【发布时间】:2026-01-19 16:20:08
【问题描述】:
我有一个程序可以使用我的自定义密码、文本文件和无损媒体文件进行编码和解码,但问题是超过 2MB 时它会崩溃。
void doTheRabi(File f, byte[] hashedPass) {
try {
// BufferedReader br = new BufferedReader(new InputStreamReader(new
// FileInputStream(f))); // legge il file
// String response = new
// String(Files.readAllBytes(Paths.get(f.getAbsolutePath()))); // scrive tutto
// il file in memoria
FileReader fr = new FileReader(f);
BufferedReader br = new BufferedReader(fr);
String response = new String(); // ASSEGNO IL CONTENUTO DEL FILE IN QUESTA STRINGA
for (String line; (line = br.readLine()) != null; response += line + "\n")
;
response = response.replace("\n", "newline").replace("\r", "newrow"); // rimpiazzo le new line con "newline"
// e "newrow"
byte[] encodedfile = response.getBytes(StandardCharsets.UTF_8); // trasformo il file in byte
byte[] result = new byte[encodedfile.length]; // variabile temporanea
int hpc = 0;
for (int i = 0; i < result.length; i++) {
result[i] = (byte) (encodedfile[i] + hashedPass[hpc++]); // algoritmo rabi
if (hpc == hashedPass.length) {
hpc = 0;
}
}
String encodedresult = Base64.getEncoder().encodeToString(result); // restituisco il risultato in base64
FileWriter fw = new FileWriter(f);
PrintWriter pw = new PrintWriter(fw);
pw.print("");
pw.append(encodedresult /* + "extension=" + extString */); // scrivo nel file tutto il risultato
pw.flush();
pw.close();
fw.close();
br.close();
String path = f.getAbsolutePath();
String newName = path + ".rab1";
f.renameTo(new File(newName));
} catch (Exception e) {
console.appendText("Error: " + e.getMessage() + "\n");
e.printStackTrace();
}
}
// operazione inversa
void killTheRabi(File f, byte[] hashedPass) {
try {
BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(f)));
String response = new String();
for (String line; (line = br.readLine()) != null; response += line)
;
byte[] decodedfile = Base64.getDecoder().decode(response);
byte[] result = new byte[decodedfile.length];
int hpc = 0;
for (int i = 0; i < result.length; i++) {
result[i] = (byte) (decodedfile[i] - hashedPass[hpc++]);
if (hpc == hashedPass.length) {
hpc = 0;
}
}
String resultString = bytesToString(result);
String finalres = resultString.replace("newline", "\n").replace("newrow", "\r");
FileWriter fw = new FileWriter(f);
PrintWriter pw = new PrintWriter(fw);
pw.print("");
pw.append(finalres);
pw.flush();
pw.close();
fw.close();
br.close();
String path = f.getAbsolutePath();
String newName = path.replace(".rab1", "");
f.renameTo(new File(newName));
} catch (Exception e) {
console.appendText("Error: " + e.getMessage() + "\n");
e.printStackTrace();
}
}
我做错了什么?我认为这是因为内存已满,因为java使用虚拟机,但我不知道提高内存使用率的方法,也许使用缓冲区但我还没有使用它们?
【问题讨论】:
-
你得到什么错误信息?
-
它只是冻结
-
这不一定是错误。很可能是您的代码仍在处理您的数据,那是另一回事
-
不要把所有东西都保存在内存中,你可以一个接一个地工作。而且您组装字符串
response的方法效率极低。了解如何使用StringBuilder。 -
您需要将
response设为StringBuilder而不是String。
标签: java encryption memory-management