hdu 1201(日期计算)

/*
  Name: 日期计算 
  Author: Try_86
  Date: 10/04/12 21:42
*/

#include <cstdio>
#include <iostream>

using namespace std;

int days[13] = {0, 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};

bool isLeap(int year) {//判断闰年 
    if ((year%400==0) || (year%4==0&&year%100!=0)) return true;
    return false;
}

int solve(int year, int month, int day) {
    if (isLeap(year) && month==2 && day==29 && !isLeap(year+18)) return -1;
    int sumDays = days[month] + day;
    if (isLeap(year+18) && month>2) ++sumDays;
    for (int i=1; i<18; ++i) {
        sumDays += 365;
        if (isLeap(year+i)) ++sumDays; 
    }
    if (isLeap(year)) sumDays += 366 - days[month] - day;
    else sumDays += 365 - days[month] - day;
    if (isLeap(year) && month>2) --sumDays;
    return sumDays; 
}

int main() {
    int t;
    scanf ("%d", &t);
    while (t--) {
        int year, month, day;
        scanf ("%d-%d-%d", &year, &month, &day);
        int ans = solve(year, month, day);
        printf ("%d\n", ans);
    }
    return 0;
}